Digital‑to‑Analog Converter Calculator

Binary weighted resistor DAC and R‑2R ladder DAC, worked out side by side.

Name
Pragyan Das
Roll No.
B24PH1019
Subject
Electronics

Aim

This page was made to go along with my written assignment on digital‑to‑analog converters. The assignment explains how the two circuits work; this page lets you actually try them — put in any digital number and it works out the analog voltage that comes out, step by step, for both types at once.

Everything runs inside your own browser. Nothing is sent anywhere and nothing is stored.

1

Set up the converter

A DAC takes a number written in 0s and 1s and turns it into one steady voltage. Choose how many bits the converter has, the reference voltage it works from, and the resistor values. Then flip the switches to enter your digital number.

Gives 16 different output levels.

The fixed supply the switches connect to.

The smallest resistor in the circuit.

Sets how much the op‑amp magnifies.

Digital input — flip a switch up for 1, down for 0

input = 10102 = 1010
2

Analog output

Both circuits are given the same digital input, the same Vref and the same resistors, so you can see straight away how their outputs differ.

Type one

Binary weighted resistor DAC

Output voltage

—
Step size (resolution)
—
Full scale output
—
Current into op‑amp
—
Largest resistor needed
—

Type two

R‑2R ladder DAC

Output voltage

—
Step size (resolution)
—
Full scale output
—
Current into op‑amp
—
Largest resistor needed
—

The minus sign appears because both circuits use the op‑amp in its inverting mode, so the output comes out on the negative side. Its size is what matters. Also notice that percentage resolution depends only on the number of bits: it is 6.6667 % for 4 bits, the same for both circuits.

3

The working, bit by bit

Each bit that is a 1 pushes its own share of current into the op‑amp, and the output is just all those shares added up. A bit that is 0 contributes nothing, because its switch is connected to ground.

Contribution of each bit to the output
Bit Place value State Binary weighted R‑2R ladder
4

Resistors each circuit needs

This is the real reason almost every converter you can buy uses the ladder. The binary weighted circuit needs a different resistor for every bit, each one twice the last, while the ladder manages with only two values no matter how many bits it has.

Resistor values, taking R = 1 kΩ
Bit Binary weighted needs Its value R‑2R needs Its value

5

Output as the input counts up

If you feed in 0, then 1, then 2 and so on, the output does not rise smoothly. It climbs in equal jumps, one jump per step, which is why a DAC output is drawn as a staircase. Drag the sweep slider above and watch the marker move.

Binary weighted R‑2R ladder
Size of the output voltage against the digital input. Both staircases have the same number of steps, but each binary weighted step is twice as tall, so for the same resistors it reaches about twice the voltage.
6

The two circuits

Both diagrams are drawn for 4 bits, with the switches set to 1010 as an example. In each one, a switch at 1 connects its resistor to Vref and a switch at 0 connects it to ground.

Binary weighted resistor DAC. Every bit gets its own resistor, and the values double as you go towards the LSB: R, 2R, 4R, 8R. The op‑amp adds up the four currents, so the smaller resistor of the MSB lets through the biggest share.
R‑2R ladder DAC. The same repeating rung of one R and one 2R is used again and again. At every rung the current splits into two equal halves, so each bit automatically gets half the current of the bit above it — without ever needing a big resistor.

Both circuits end in the same place: an op‑amp wired as an inverting adder. The resistor Rf in the feedback path decides how many volts come out for each unit of current flowing in.

7

Comparing the two

Short comparison
Binary weightedR‑2R ladder
Resistor values neededn different ones: R, 2R, 4R, 8R …Only two: R and 2R
For an 8 bit converterLargest resistor is 128 × RStill just R and 2R
Making it accuratelyDifficult, because very large and very small resistors must all be exactEasy, because matching two equal resistors is simple
Number of partsFewer parts, easier to followAbout twice as many resistors, but all alike
Adding one more bitNeeds a brand new, doubled resistor valueJust add one more identical rung
Size of one stepVref × (Rf/R) ÷ 2n−1Vref × (Rf/R) ÷ 2n
Where it is usedTeaching, and converters with very few bitsAlmost every DAC chip made today